Question

determinati numarul de moli de atomi din: a) 6g oxigen b) 6g hidrogen c) 80g calciu d) 15g nichel​

Answer 1

Răspuns:

1. a) n = m/M = 6/2 = 3 moli H2

1 mol H2...................2*NA = 2*6,022*10^23 atomi

3 moli H2.......................x = 36,132*10^23 atomi

b) n = m/M = 40/40 = 1 mol Ca

1 mol Ca = NA = 6,022*10^23 atomi

c) n = m/M = 60/2 = 30 kmoli = 30000 moli H2

1 mol H2...................12,044*10^23 atomi

30000 moli H2............x = 3,6132*10^28 atomi

d) n = m/M = 15/31 = 0,4838 kmoli = 483,87 moli P

nr atomi = 483,87*NA = 2,91387*10^26 atomi

2. a) n = m/M => m= n*M = 5*28 = 140g N2

b) n = m/M => m = 2*24 = 48g Mg

c) n = m/M => m = 3*56 = 168g Fe

d) m = 4*59 = 236g Ni

e) .......

f) m = 2,5*20 = 50kg = 50000g Ne