Question

Determinați numărul natural n pentru care 2n+2 este divizor al lui 20.
✨va rog repede✨​

Answer 1

2n+2€D20={-1,+1,-2,+2,-4,+4,-5,+5,-10,+10,-20,+20}

2n+2=-1=>2n=-1-2=>2n=-3=>n=-3/2

2n+2=1=>2n=1-2=>2n=-1=>n=-1/2

2n+1=-2=>2n=-3=>n=-3/2

2n+1=2=>2n=1=>n=1/2

2n+1=4=>2n=3=>n=3/2

2n+1=-4=>2n=-5=>n=-5/2

2n+1=5=>2n=4=>n=2

2n+1=-5=>2n=-6=>n=-3

2n+1=10=>2n=9=>n=9/2

2n+1=-10=>2n=-11=>n=-11/2

2n+1=20=>2n=19=>n=19/2

2n+1=-20=>2n=-21=>n=-21/2

n€{-3/2, -1/2, -11/2, -21/2 , -5/2, 1/2,3/2,2,9/2,19/2}