Question

Determinati numerel x,y,z stiind ca x\2 =y\3=z/4 si 2x+y+5z=81
am nevoie repede
,,/“ este supra

Answer 1

$\frac{x}{2} = \frac{y}{3} = \frac{z}{4} = k$

$\frac{x}{2} = k = > x = 2k$

$\frac{y}{3} = k = > y = 3k$

$\frac{z}{4} = k = > z = 4k$

2x + y + 5z=81 inlocuim cu k

$2 \times 2k + 3k + 5 \times 4k = 81 \\ \\ 4k + 3k + 20k = 81 \\ 27k = 81 \\ k = 81 \div 27 \\ k = 3$

$x = 2k \: si \: k = 3 = > x = 2 \times 3 = 6$

$y = 3k \: si \: k = 3 = > y = 3 \times 3 = 9$

$z = 4k \: si \: k = 3 = > z = 4 \times 3 = 12$

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