Question

determinati numerele a,b si c direct proportionale cu 5,8 si 12 , stiind ca a(la puterea 2) + b(la puterea 2)+c(la puterea 2)=233

Answer 1

a/5 = b/8 = c/12 = k
a = 5k
b = 8k
c = 12k
a² + b² + c² = 233
(5k)² + (8k)² + (12k)² = 233
25k² + 64k² + 144k² = 233
233k² = 233
k² = 233/233
k² = 1
k = √1
k = 1
a = 5 * 1 = 5
b = 8 * 1 = 8
c = 12 * 1 = 12