Question

Determinati numerele de forma abc stiinca
Abc0 +2abc+ 1abc=4476

Answer 1

1000*a+100*b+10*c+2000+100*a+10*b+c+1000+100*a+10*b+c=4476
1200*a+120*b+12*c+3000=4476
1200*a+120*b+12*c=1476      |:12
100*a+10*b+c=123
Analiza:
100*a are ultima cifra 0
10*b are ultima cifra 0
=> c =3

100*a+10*b+3=123
100*a+10*b=120
Observam ca a<2 =>a=1 =>
100+10*b=120
10*b=20 => b=2

 abc =123

verificare: 1230+2123+1123=4476  -ok!