Question

determinati numerele naturale de 2 cifre care impartite la suma cifrelor lor dau catul 6si restul 1...cu rezolvare

Answer 1

ab : (a+b) = 6 rest 1
ab = 6×(a+b)+1
10×a+b = 6×a+6×b+1
10×a-6×a = 6×b-b+1
4×a = 5×b+1
a diferit de 0
a>b
daca a = 4 =>5×b+1 = 16 => 5×b=15 =>b = 15:5 => b = 3
daca a = 9 => 5×b+1 = 36 => 5×b = 35 => b = 35:5 => b = 7

ab = 43
ab = 97

verificare:
43 : 7 = 6 rest 1
97 : 16 = 6 rest 1