Question

determinati numerele naturale de doua cifre care se micsoreaza cu 45 daca se schimba ordinea cifrelor

Answer 1

ab = numarul de doua cifre

ab = ba + 45

10a + b = 10b + a + 45

10a - a = 10b - b + 45

9a - 9b = 45

9×(a - b) = 45 | : 9

a - b = 5

9 - 4 = 5 => (a; b) = (9; 4)
8 - 3 = 5 => (a; b) = (8; 3)
7 - 2 = 5 => (a; b) = (7; 2)
6 - 1 = 5 => (a; b) = (6; 1)

asadar, ab = 94; 83; 72; 61 .
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94 = 49 + 45
83 = 38 + 45
72 = 37 + 45
61 = 16 + 45