Question

Determinați numerele naturale n,pentru care 8 la puterea n+8 la puterea n+1=18×2 la puterea 2003

Answer 1

8^n + 8^n+1 = 18 × 2^2003

8^n×(1 + 8) = 18 × 2^2003

8^n × 9 = 18 × 2^2003

2^3n = 18 : 9 × 2^2003

2^3n = 2 × 2^2003

2^3n = 2^2004

3n = 2004

n = 2004 : 3

n = 668