Question

Determinati numerele prime a,b,c stiind ca 2a+5b+6c=74

Answer 1

2a+5b+6c=74⇒74 ,2a ,6c-numere prime⇒2 si 6-numere ,a ,c∈N;
⇒5b-numar ,b∈N;
⇒b=2;
⇒2a+10+6c=74
⇒2a+6c=64⇒6c<64⇒c=[2,3,5,7];
⇒2a+12=64⇒2a=52⇒a=26⇒nu este numar prim;
⇒2a+18=64⇒2a=46⇒a=23⇒numar prim;
⇒2a+30=64⇒2a=34⇒a=17⇒numar prim;
⇒2a+42=64⇒2a=22⇒a=11⇒numar prim;
⇒b=2;
⇒a=[23,17,11];
⇒c=[3,5,7];