Question

Determinati numerele reale a si b , stiind ca $a^{2} + b^{2} -2a + 6b +10=0$

Answer 1

(a²-2a+1)+(b²+6b+9)=0
(a-1)²+(b+3)²=0
(a-1)²=0=>a-1=0=>a=1
(b+3)²=0=>b+3=0=>b=-3