Question

DeterminatI pe a si b stiind ca egalitatile sunt adevarate simultan a×a+b×b=25,a+a+b+b=14

Answer 1

[tex] a^{2}+ b^{2}=25 \\ 2a+2b= 14, a+b=7, a=7-b \\ 49-14b+ b^{2} + b^{2}=25 \\ 2 b^{2}-14b+24=0 \\ b^{2}-7b+12=0 \\ b=3 sau b=4 \\ a=4saua=3 [/tex]