Question

Determinati perechile (x,y) de numere intregi care verifica relatia
x² + y² - 4x + 2y - 8 = 0

Answer 1

[tex]x^2-2\cdot x\cdot 2+2^2+y^2+2\cdot y \cdot 1+1^2-4-1-8=0\\ (x-2)^2+(y+1)^2=13\\ (x-2)^2=4 \ si (y+1)^2=9\ =>x-2=\pm 2 \ si\ y+1=\pm 3=>....\\ (x-2)^2=9\ si (y+1)^2=4\ => x-2=\pm 3 \ si\ y+1=\pm 2=>.... \\[/tex]