Question

determinati suma tuturor numerelor naturale care dau catul 130 prin impartirea la 7.sa fie dezvoltat pls

Answer 1

Răspuns:

R<I

R∈{0,1,2,3,4,5,6}

a:7=130 rest 0=>a=7·130+0=910

a:7=130 rest 1=>a=7·130+1=911

.

a:7=130 rest 6=>a=7·130+6=916

nr sunt:910,911,912,913,914,915,916

S=910+911+912+913+914+915+916=6391