Question

Determinați valoarea lui a din.      [48+50×100÷(28÷a+3×2)-14]×[(50-4×5)+(143×6)]=42316

Answer 1

[48+50×100÷(28÷a+3×2)-14]×[(50-4×5)+(143×6)]=42316

[48+50×100÷(28÷a+3×2)-14]×[(50-20)+858]=42316

[48+50×100÷(28÷a+3×2)-14]×(30+858)=42316

[48+50×100÷(28÷a+3×2)-14]×888=42316

48+50×100÷(28÷a+3×2)-14=42316/888 - se simplifica fractia

48+5000:(28:a+6)=10579/222+14

5000:(28:a+6)=(10579+14*222)/222-48

5000:(28:a+6)=(13687-48*222)/222

5000:(28:a+6)=3031/222

28:a+6=(5000*222)/3031

28:a=(1110000-6*3031)/3031

a=(3031*28)/1091814

a=42434/545907