Question

Determinati valorile intregi nenule ale lui x pentru care 7-2x | 5x+8

Answer 1

7-2x I 5x+8 / (-2)
7-2x I 7- 2x /    5
=> 7-2x I 35 -10x  +10x + 16
=> 7-2x I51
=> 7-2x apartine D 51 adica { -51,-17,-3,-1,1,3,17,51} /-7
-2x apartine { -58,-24,-10,-8,-6,-4,,10,44 }/  :(-2)
x apartine {-29,-12,-5,-4,-2,5,22 }