Question

Determinati valorile lui x din :
A) [200-(64+x•12+2•11)]•(50-24•2+13•5-9•5)=1980.
B) [(32•66•2:24-125):3+5•x]-24•3+888:8=61.
C) 3000-{123•4-[(x:3-271)-3•12]+125•12}=1243.
D) 49326-125•8:[484:4-(x•2+5•3)]-24325:5=44451.
Va roggg daca puteti sa mi-l rezolvati !!!

Answer 1

deschid paranteza patrata 200-( 64+x ori 12+22) inchid si paranteza patrata ori (50-48+65-45)=1980
deschid patrata 200-( 86+ xori12)inchid patrata ori 22=1980
deschid patrata 200-(86+x ori 12)=1980/22
deschid patrata 200-( 86+x ori 12)=90
-(86+ x ori12)= 90-200
-(86+x ori 12) = -110 deci 86+ x ori 12= 110
x ori 12= 110-86
xori 12= 24 deci x= 24/12 deci x=2

la punctul b 32 ori 66 ori 2 impartit la 24 fac 176
deci: deschid patrata si deschid si rotunda 176-125)/3+5ori x inchid patrata- 72+111= 61
(51/3+5orix)-72=61-111
(17 +5 orix) -72= -50
17+5 ori x= -50+72
17+ 5 ori x= 22
5 ori x= 22-17
5 ori x= 5 deci x egal 5/5 deci x egal 1
 asa faci si pt celelelte spor