Question

determinati viteza unei particule care are energia cinetica de 3,5 ori mai mare decat energia de repaus

Answer 1

Wc=3,5W₀

Wc=W-W₀=>Wc=mc²-m₀c²

mc²-m₀c²=3,5m₀c² |:c²=>m=4,5m₀

m=m₀γ<=>4,5m₀=m₀γ=>γ=4,5

γ=1/√(1-v²/c²) |()²=>γ²=1/(1-v²/c²)=>1-v²/c²=1/γ²<=>-v²/c²=1/γ²-1<=>-v²/c²=1/4,5²-1<=>-v²/c²=-0,95=>v=√0,95c²=0,97c

v=0,97c