Question

Determinati x care verifica egalitatile:
[(x+2) / ( x-1) ] -[ (2x-1) / 3 ] = (x-1) /6

Answer 1

$\frac{x+2}{x-1} - \frac{2x-1}{3} = \frac{x-1}{6}$
Aducem ecuatia la acelasi numitor.

$\frac{6(x+2)}{6(x - 1)} - \frac{2(x-1)(2x-1)}{6(x - 1)} = \frac{(x-1)(x-1)}{6(x - 1)}$

$6x+12 -2(2 x^{2} -3x + 1) = x^{2} -2x +1$

$6x + 12 -4 x^{2} + 6x - 2 = x^{2} -2x + 1$

$-4 x^{2} - x^{2} +6x+6x+2x + 12 - 2-1=0$

$-5 x^{2} + 14x -9 =0$

[tex] x_{12} = \frac{-14 +/- \sqrt{196 -180} }{10} [/tex]

Nu am terminat adunarea