Question

determinati x pentru care au loc egalitatile 121in baza 10 = x in baza 2

Answer 1

121:2=60 rest 1

60:2=30 rest 0

30:2=15 rest 0

15:2=7 rest 1

7:2=3 rest 1

3:2=1 rest 1

1:2=0 rest 1

0:2=0

Citim resturile impartirilor de jos in sus si avem:

x=1111001(2)

Verificare: 2^6 + 2^5 + 2^4 + 2^3 + 2^0 = 64+32+16+8+1 = 121, deci corect.