Question

Determinati x,y si z, stiind ca : x-y supra 2 = y+z supra 8 = z supra 6 si x+2z=48 Va rog !!!! Dau coroana si multumesc !

Answer 1

x-y supra 2=y+z supra 8=z supra 6 = k (egalezi cu k) ==> x-y supra 2 = k ==> x-y = 2k y+z supra 8 =k ==> y+z=8k z supra 6 =k ==> z= 6k x-y=2k y+z=8k z=6k Inlocuiesti in a doua relatie: y+6k =8k ==> y=2k x-y=2k==> x-2k=2k==> x=4k x+2z=48==> 4k+2*6k=48 ==> 4k+12k=48==>k=3 z=6*3=18 y=2*3=6 x=4*3=12