Question

Determinatii numerele naturale de forma abcd barat. scrise in baza zece, stiind ca : 24*a+39*b+cd barat=61

Answer 1

24a + 39b + cd = 61
Daca b = 2 => 24a + 78 + cd = 61, 61 < 71 (F) => b = 0,1
b = 1 => 24a + 39 + cd = 61 => 24a + cd = 61 - 39 = 22
1) a = 1 => 24 + cd = 22, 22 < 24 (F) => a = 0
2) a = 0 (F), a e nenul

b = 0 => 24a + cd =  61 
1) a = 3 => 24 x 3 + cd = 61 => 72 + cd = 61, 61<72 (F) => a = 1,2
2) a = 2 => 24 x 2 + cd = 61 => 48 + cd = 61 => cd = 61 - 48 = 13, 2013
3) a = 1 => 24 + cd = 61 => cd = 61 - 24 = 37, abcd = 1037

abcd = 1037,2061