Question

Determinatinumarul natural n stiind ca :25la puterea n+ 1=125 la puterea 4

Answer 1

$25^{n+1} = 125^4\Rightarrow (5^2)^{n+1} = (5^3)^4 \Rightarrow 5^{2(n+1)}=5^{12}$

$\Longrightarrow 2(n+1)=12|_{:2}\Longrightarrow n+1=6$