Question

Diferenta a doua nr naturale este 95 impartind numarul mai mare la numarul mic obtinem  catul 11 si restul 5

Answer 1

a-b=95
a:b=11 rest 5
a=11b+5
11b+5-b=95
10b=95-5=90
b=9
a=95+9=104

Answer 2

a-b=95
a:b=11,r=5=>a=11b+5
Inlocuim in prima ecuatie
=>11b+5-b=95=>10b+5=95=>10b=95-5=>10b=90=>b=90:10=>b=9
Dar a=11b+5 si b=9=>a=9x11+5=99+5=104