Question

Dintr-o proba de 10,6 mg compus A s-au obtinut 26,4 .g Co2 , 5,4 mg H2O si 2,24 mL (c.n) azot .Masa molara a compusului A este 53 g / mol
Determinati formula moleculara.

Answer 1

10,6mg proba.....26,4mgCO2.....5,4mgH2O.....2,24mlN2
53g.......................m=132gCO2.......27gH2O.......11,2 LN2

n,molCO2=n,molC= 132g/44g/mol= 3molC..
n,molH2o= 27g/18g/mol=1,5molH2O-----------------> n,H=3mol
n,molN2= 11,2l/22,4l/mol= .0,5molN2------------> n,N=1molN
COMPUSUL este: C3H3N....