Question

doar b si c va rog urgent dau coroana multumesc​

Answer 1

Răspuns:

Explicație pas cu pas:

b)ΔOMB asemenea cu ΔAOD       O1=O2    opuse la varf

                                                          ∠DAO=∠OMB   alterne int

DO/OB=AO/OM=AD/BM=2    

AO+OM/OM=2+1/1           AM/OM=3      AM=13 dam    OM=13/3 dam

AO+OM/OA=3/2               AM/OA=3/2                            OA=13×2/3 dam

c) A dcmo=Aabcd-(Aabd-+Abom)

Aabcd=10×12=120 dam²

Aabd=10×12/2=10×6=60 dam²

Abom=OH×BM/2

In ΔOMH      OH²=OM²-(BM/2)²= (13/3)²- (5/2)²=(13/3-5/2)(13/3+5/2)==(26-15)12×(26+15)12=11×41/144 dam²

Adcmo=120-(60-11×41/144)=120-(8640-451)144=120-8189/144=120-56,86=63,14 dam²

Adcmo=