Question

doar ce știți.. mulțumesc anticipat

Answer 1

1)
t+f=60
t/f=2,75⇒t=2,75·f
2,75·f+f=60
3,75·f=60
f=60/3,75
f=16
t=60-16
t=44

t-x=3·(f-x)
44-x=3·(16-x)
44-x=48-3x
3x-x=48-44
2x=4
x=2, deci in urma cu 2 ani

2b)
f(x)=3x-1
A(m, m+11)∈Gf⇒m=f(m+11)
m=3(m+11)-1
m=3m+33-1
m=3m+32
3m-m=32
2m=32
m=16

3b)
Al=Pb·h
Pb=3·4√3=12√3 cm
h=AA'=3√3
Al=12√3·3√3
Al=36·3
Al=108 cm²

c)
Notezi d(C'; AB)=C'D
C'A²=A'A²+A'C'²
C'A²=(4√3)²+(3√3)²
C'A²=48+27
C'A²=75
AD=AB/2=4√3/2=2√3 cm
In ΔC'DA:
C'D²+AD²=C'A²
C'D²+(2√3)²=75
C'D²=75-12
C'D²=63
C'D=√63
C'D=3√7 cm

Answer 2

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