Question

Doar punctul a și c va rog și modul de rezolvare la ele​

Answer 1

Răspuns:

ti le trimit pe rand......

Answer 2

a)

$\it \dfrac{^{3)}3}{\ 4} -\dfrac{5}{12}+\dfrac{^{4)}2}{\ 3}=\dfrac{9-5+8}{12}=\dfrac{12}{12}=1$

c')

$\it \dfrac{5}{12}:\Big(\dfrac{^{3)}3}{\ 4}-\dfrac{^{4)}1}{\ 3}\Big)-\dfrac{1}{6}:\Big(\dfrac{7}{24}-\dfrac{^{3)}1}{\ 8}\Big)=\dfrac{5}{12}:\dfrac{9-4}{12}-\dfrac{1}{6}:\dfrac{7-3}{24}=\\ \\ \\ =\dfrac{5}{12}:\dfrac{5}{12}-\dfrac{1}{6}:\dfrac{\ 4^{(4}}{24}=1-\dfrac{1}{6}:\dfrac{1}{6}=1-1=0$