Question

dovedește efectuând calculele:
a) 1+918:{[12+3×(576:12-4×12)]:4+6}=
m) [(348:12-676:26)×3:9-1]×15+1=

Answer 1

efectuam calculele tinand cont de regula operatiilor: mai intai calculam inmultiri, impartiri, adunari si scaderi in ordinea in care apar.
a) 1 + 918 ÷ {[12 + 3 × (48-48)] ÷ 4 + 6}
= 1 + 918 ÷ [(12 + 3 × 0) ÷ 4 + 6]
= 1 + 918 ÷ [(12 + 0) ÷ 4 + 6]
= 1 + 918 ÷ (12 ÷ 4 + 6)
= 1 + 918 ÷ (3 + 6)
= 1 + 918 ÷ 9
= 1 + 102
= 103

m) [(29 - 26) × 3 ÷ 9 - 1] × 15 + 1
= (3 × 3 ÷ 9 - 1) × 15 + 1
= (9 ÷ 9 - 1) × 15 + 1
= (1 - 1) × 15 + 1
= 0 × 15 + 1
= 0 + 1
= 1