Question

.
e) (112011. 41005) : [(222):1201
f) 22 : 2212 + 332 : 331.3.

Answer 1

Răspuns:

e) (11^2011*4^1005)/((22^2)^5)^201

(11^2011*4^1005)/(22^10)^201

(11^2011*4^1005)/22^2010

11^2011*4^1005supra 22^2010

11^2011*2^2010supra2^2010*11^2010

11^2011supra11^2010

11

f) 2^23/2^21/2+3^32/3^31*3

2+3^32/3^31*3

2+3^

2+9

11

Explicație pas cu pas: