Question

E(x) = (2x +1)2 − (x −1)2 + (x +1)(x −1)− 3x2 +12 ?

Answer 1

Răspuns:E(x) = (2x+1)² - (x-1)² + (x-2)(x+2) - 3x² +14 =

= 4x² +4x +1 - x² + 2x - 1 +x² -4 -3x² +14 = x² + 6x +10

Explicație pas cu pas:

Answer 2

E(x)= (2x+1)^2 - (x-1)^2 + (x+1)(x-1) - 3x^2 + 12

E(x)= (2x+1)² - (x-1)² + (x+1)(x-1) - 3x² + 12

$\it E(x)=(2x+1)^2-(x-1)^2+(x+1)(x-1)-3x^2+12=\underline{\underline{4x^2}}+4x+1-\\ \\ -\underline{\underline{x^2}}+2x-1+x^2-1-\underline{\underline{3x^2}}+12=x^2+6x+11$