Question

E(x)=$\frac{(x+1)^{2}-4}{x} : \frac{ x^{2} -x}{ x^{2} }$ unde x este număr real, x≠0 şi x≠1.

Answer 1

[tex]E(x)= \frac{(x+1)^2-4}{x} : \frac{x^2-x}{x^2} \\ E(x)= \frac{(x+1)^2-2^2}{x} * \frac{x^2}{x(x-1)} \\ E(x)= \frac{(x+1-2)(x+1+2)}{x} * \frac{x}{x-1} \\ E(x)= \frac{(x-1)(x+3)}{(x-1)} \\ E(x)=x+3 [/tex]