Question

E(x) = (x+2/x-5 - x-5/x+2) * x la a doua -4x -5/2x la a doua-x-3. Cine poate sa ma ajute va rog Nu pot sa promit coronita pt ca sunt noua dar raman datoare pentru cine stie

Answer 1

[tex]E(x)=(\frac{x+2}{x-5}-\frac{x-5}{x+2})\cdot \frac{x^2-4x-5}{2x^2-x-3}\\ Descompunem\ numitorii\ separat:\\ x^2-4x-5=x^2-5x+x-5=x(x-5)+(x-5)=(x+1)(x-5)\\ 2x^2-x-3=2x^2+2x-3x-3=2x(x+1)-3(x+1)=\\ =(x+1)(2x-3)\\ Revenind:\\ E(x)=\frac{(x+2)^2-(x-5)^2}{(x-5)(x+2)}\cdot \frac{(x+1)(x+5)}{(x+1)(2x-3)}\\ E(x)=\frac{(x+2-x+5)(x+2+x-5)}{(x+2)(2x-3)}\\ E(x)=\frac{7(2x-3)}{(x+2)(2x-3)}\\ \boxed{\bold{E(x)=\frac{7}{2x-3},\forall\ x\in R-\{-2,-1,\frac{3}{2},5\}}}}[/tex]