Question

E3 a,b,c
E4 b
Va rog faceti cu rezolvare, imi trebe pana azi pe seara. Dau coroana PLS​

Answer 1

Răspuns:

Rezolvarea mai jos

Explicație pas cu pas:

Salutare!

E3 a)(4/9)^(x+1)×(27/8)^x=2/3

(2/3)^(2x+2)×(2/3)^-3x=(2/3)¹

(2/3)^(-x+2)=(2/3)¹

-x+2=1

-x=1-2

-x=-1

x=1

Formula folosita : (a/b)^n=(b/a)^-n

b)(3/11)^(3x-10)=(11/3)^(7x-10)

(3/11)^(3x-10)=(3/11)^(-7x+10)

3x-10=-7x+10

3x+7x=10+10

10x=20

x=20:10=2

c)(0,25)^(3-x)=256/2^(x+5)

2^(-6+2x)=2^(3-x)

-6+2x=3-x

2x+x=3+6

3x=9

x=9:3=3

E4 b)3^(2x+1)+3^2x-3^(2x-1)=297

(9+3-1)×3^(2x-1)=297

11×3^(2x-1)=297

3^(2x-1)=27

3^(2x-1)=3³

2x-1=3

2x=3+1

2x=4

x=4:2

x=2