Question

ecuatia urmatoare cum se face vreu pas cu pas 3000-{123ori4-[(x:3-271)-3ori 12]+125ori12}=1243

Answer 1

[tex]3000-{123*4-[(x:3-271)-3*12]+125*12}=1243 \\ 3000-{492-[(x:3-271)-36]+1500}=1243 \\ Facem~mersul~invers~si~scadem~din~3000~pe~1243: \\ 492-[(x:3-271)-36]+1500=3000-1243 \\ 492-[(x:3-271)-36]+1500=1757 \\ Acum~facem~la~fel~si~scadem~din~1757~pe~1500: \\ 492-[(x:3-271)-36]=1757-1500 \\ 492-[(x:3-271)-36]=257 \\ Din~nou~,~de~data~asta~din~492~il~scadem~pe~257: \\ (x:3-271)-36=492-257 \\ (x:3-271)-36=235 \\ Acum~il~adunam ~pe~235~cu~36: \\ x:3-271=235+36 \\ x:3-271=271[/tex]
$Acum~il~adunam~pe~271~cu~271: \\ x:3=271+271 \\ x:3=542 \\ x=542*3 \\x=1626$
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