Question

Efectuand calculele,obtinem :
a) x(√5-√2)+x(2√5+3√2)-4√5x+4√2x=
b)(-108x²y³):(-36xy²)+60x³y⁴:(-15x²y³)-24x³y²:(-4x²y)=
c)√8xy²-√50x²y+√98x²y²-√32xy²+√72x²y=

Answer 1

a) x(√5-√2)+x(2√5+3√2)-4√5x+4√2x=
x(√5-√2+2√5+3√2)-4√5x+4√2x=
x(3√5+2√2)-4√5x+4√2x=
-x√5+6√2x=x(6√2-√5)

b)(-108x²y³):(-36xy²)+60x³y⁴:(-15x²y³)-24x³y²:(-4x²y)=
       3xy-4xy+6xy=
        5xy
c)√8xy²-√50x²y+√98x²y²-√32xy²+√72x²y=
   presupunand ca doar cifrele sunt sub radical⇒
2√2xy²-5√2x²y+7√2x²y²-4√2xy²+6√2x²y=
-2√2xy²+√2x²y+7√2²y²=
√2xy(-2y+x+7xy)