Matematică, întrebare adresată de cami0202, 9 ani în urmă

Efectuati:
♣ 2/3 + (x+1)/2=5-(4-x)/6 .....(x+1)/2 inseamna x+1 suprs 6 si cealalta la fel..
♣ 6x/5 -x=x/3+8x
♣ 1/4*{1/4*[1/4*(1/4*x+1)+4]+1}+4=5
♣ 0,(6)x+2-0,(3)=4-2(x=1)+ 3,(6)
♣ 12 intregi si 1/3: {[2intregi si 3/4:(1 intreg si 2/3+1 intreg si 7/8*x)]*8/11+1 intreg si 2/3}=5
♣ 0,(1x)+0,(2x)+...+0,(9x)=x .....aici 0,(1x); 0,(2x); etc au liniuta aia deasupra(nu stiu sa o pun... mi-am zis sa va anunt si pe voi de liniuta)


cami0202: este doar 5
renatemambouko: la exercitiul 4 ai intr-o paranteza x=1 ????
cami0202: am x+1 in paranteza...
cami0202: sunt pe laptos si am uitat sa apas pe shift si atunci a iesit = .... scuze.. :3
renatemambouko: 2/3 + (x+1)/2=5-(4-x)/6
4+3x+3=30-4+x
2x=19
x=19/2
renatemambouko: 6x/5 -x=x/3+8x
18x-15x=5x+120x
122x=0
x=0
renatemambouko: 1/4*{1/4*[1/4*(1/4*x+1)+4]+1}+4=5
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=5-4
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=1
{1/4*[1/4*(1/4*x+1)+4]+1}=4
1/4*[1/4*(1/4*x+1)+4]=4-1
1/4*[1/4*(1/4*x+1)+4]=3
1/4*(1/4*x+1)+4=12
1/4*(1/4*x+1)=8
1/4*x+1=32
1/4*x=31
x=124
renatemambouko: 0,(6)x+2-0,(3)=4-2(x+1)+ 3,(6)
0,(6)=6/9=2/3
0,(3)=3/9=1/3
3,(6)=(36-3)/9=33/9=11/3
2x/3+2-1/3=4-2x-2+11/3
2x/3=2-2x-2+11/3+1/3
2x/3=-2x+4
2x=-6x+12
8x=12
x=12/8=3/2
renatemambouko: 12 intregi si 1/3: {[2intregi si 3/4:(1 intreg si 2/3+1 intreg si 7/8*x)]*8/11+1 intreg si 2/3}=5
37/3:{[11/4:(5/3+15x/8)]*8/11+5/3}=5
[11/4:(5/3+15x/8)]*8/11+5/3=37/15
11/4:(5/3+15x/8)*8/11=37/15-5/3
11/4:(5/3+15x/8)*8/11=(37-25)/15
11/4:(5/3+15x/8)*8/11=12/15
11/4:(5/3+15x/8)=4/5 *11/8
11/4:(5/3+15x/8)=11/10
5/3+15x/8=5/2
15x/8=5/2 -5/3
15x/8=(15-10)/6
15x/8=5/6
x=4/9
renatemambouko: 0,(1x)+0,(2x)+...+0,(9x)=x
(10+x)/99+(20+x)/99+ ....(90+x)/99=x
10+x+20+x+....+90+x=99x
450=90x
x=5

Răspunsuri la întrebare

Răspuns de renatemambouko
18
 2/3 + (x+1)/2=5-(4-x)/6
4+3x+3=30-4+x
2x=19
x=19/2

 6x/5 -x=x/3+8x
18x-15x=5x+120x
122x=0
x=0

1/4*{1/4*[1/4*(1/4*x+1)+4]+1}+4=5
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=5-4
1/4*{1/4*[1/4*(1/4*x+1)+4]+1}=1
{1/4*[1/4*(1/4*x+1)+4]+1}=4 
1/4*[1/4*(1/4*x+1)+4]=4-1 
1/4*[1/4*(1/4*x+1)+4]=3
1/4*(1/4*x+1)+4=12
1/4*(1/4*x+1)=8
1/4*x+1=32
1/4*x=31
x=124


 0,(6)x+2-0,(3)=4-2(x+1)+ 3,(6)
0,(6)=6/9=2/3
0,(3)=3/9=1/3
3,(6)=(36-3)/9=33/9=11/3
2x/3+2-1/3=4-2x-2+11/3
2x/3=2-2x-2+11/3+1/3
2x/3=-2x+4
2x=-6x+12
8x=12
x=12/8=3/2


 12 intregi si 1/3: {[2intregi si 3/4:(1 intreg si 2/3+1 intreg si 7/8*x)]*8/11+1 intreg si 2/3}=5
37/3:{[11/4:(5/3+15x/8)]*8/11+5/3}=5
[11/4:(5/3+15x/8)]*8/11+5/3=37/15
11/4:(5/3+15x/8)*8/11=37/15-5/3 
11/4:(5/3+15x/8)*8/11=(37-25)/15 
11/4:(5/3+15x/8)*8/11=12/15 
11/4:(5/3+15x/8)=4/5 *11/8 
11/4:(5/3+15x/8)=11/10
5/3+15x/8=5/2 
15x/8=5/2 -5/3
15x/8=(15-10)/6
15x/8=5/6
x=4/9



 0,(1x)+0,(2x)+...+0,(9x)=x
(10+x)/99+(20+x)/99+ ....(90+x)/99=x
10+x+20+x+....+90+x=99x
450=90x
x=5
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