Question

efectuati:
(7503÷61+877):500+53×11
207×9-(19×2+3×2)÷74+2296÷41
5×230-7×(512×32+2×2)+4687÷43
[493÷17-(128÷2×6+224÷8)÷22]÷27-1

Answer 1

Răspuns: Ai mai jos rezolvare

Explicație pas cu pas:

$\bf a)~ (7503: 61 + 877): 500 + 53\cdot 11=$

$\bf (123 + 877): 500+ 53\cdot11=$

$\bf 1000: 500+ 53\cdot11=$

$\bf 2 +53\cdot11=$

$\bf 2 +583=$

$\blue{\underline{~\bf 585~}}$

$\bf b)~ 207\cdot9-(19^2-3^2): 74 +2296: 41=$

$\bf 1863-(361+9): 74 +2296: 41=$

$\bf 1863-370: 74 +56=$

$\bf 1863-5 +56=$

$\purple{\underline{~\bf 1914~}}$

$\bf c)~ 5\cdot230 - 7\cdot (512:32 + 2^2) + 4687: 43=$

$\bf 1150-7\cdot (16 + 4) + 109=$

$\bf 1150-7\cdot 20 + 109=$

$\bf 1150-140 + 109=$

$\bf 1010 + 109=$

$\pink{\underline{~\bf 1119~}}$

$\bf d)~ [493: 17- (128: 2^3+ 224:8):22]: 27-1=$

$\bf [493: 17- (128: 8+ 28):22]: 27-1=$

$\bf [29- (16+ 28):22]: 27-1=$

$\bf (29- 44:22): 27-1=$

$\bf (29- 2): 27-1=$

$\bf 27: 27-1=$

$\bf 1-1=$

$\red{\underline{~\bf 0~}}$

$==pav38==$