Question

Efectuati:
A.19-2^2×[4×9:(3×2^2)]=
B.(3^2-2^3):(6^2-7×5)=
C.(4^3-23^0):3^2+2^2×8=
100
D.(2^2-3)+5:[3^2-4×(3^1-3^0)]×1^2013=
E.21^2-2×{11^2+21:(2-1)+2×[1+2^3×(1+2)+2^4-2^1]}

Answer 1

sper că te-am ajutat. o seara frumoasa