Question

Efectuati:
a)19,2-7,1=
b)27,84-4,12=
c)8,797-2,429=
d)9,64-4,2=
e)28,97-5,9=
f)24-0,12=
g)87-4,253
h)9-0,08=
i)25-4,5=
j)11,(12)-4,(23)=
k)11,(12)-4,(23)=
l)9,2(5)-6,1(3)=
m)7,(8)-3,4(5)=
n)12 intregi,3supra 4 - 7,2-0,(2)=

Answer 1

a)19,2-7,1=12,1
b)27,84-4,12=23,72
c)8,797-2,429=6,368
d)9,64-4,2=5,44
e)28,97-5,9=23,07
f)24-0,12=23,88
g)87-4,253=82,747
h)9-0,08=8,92
i)25-4,5=20,5
j)11,(12)-4,(23)=1101/99-419/99=682/99=62/9
(1112-11)/99=1101/99
(423-4)/99=419/99
k)11,(12)-4,(23)=1101/99-419/99=682/99=62/9
(1112-11)/99=1101/99
(423-4)/99=419/99
l)9,2(5)-6,1(3)=833/90-552/90=281/90
(925-92)/90=833/90
(613-61)/90=552/90
m)7,(8)-3,4(5)=71/9-311/90=(710-311)/90=399/90
(78-7)/9=71/9
(345-34)/90=311/90
n)12 intregi,3supra 4 - 7,2-0,(2)=51/4-7,2-2/9=51/4-72/10-2/9=
=(2295-1296-40)/180=959/180
12 intregi si 3/4=(48+3)/4 =51/4
0,(2)=2/9

Answer 2

$a).19,2-7,1=12,1 \\ \\ b).27,84-4,12=23,72 \\ \\ c).8,797-2,429=6,368 \\ \\ d).9,64-4,2=5,44 \\ \\ e).28,97-5,9=23,07 \\ \\ f).24-0,12=23,88 \\ \\ g).87-4,253=82,747$

$h).9-0,08=8,92 \\ \\ i).25-4,5=20,5$

$j).11,(12)-4,(23)= \frac{1101}{99} - \frac{419}{99}= \frac{682}{99} = \frac{62}{9} \\ \\ k).11,(12)-4,(23)= \frac{1101}{99} - \frac{419}{99}= \frac{682}{99} = \frac{62}{9} \\ \\ l).9,2(5)-6,1(3)= \frac{833}{90} - \frac{552}{90} = \frac{281}{90} \\ \\ m).7,(8)-3,4(5)= \frac{71}{9} - \frac{311}{90} = \frac{710}{90} - \frac{311}{90} = \frac{399}{90} = \frac{133}{30}$

$n).12 \frac{3}{4} -7,2-0,(2)= \frac{51}{4} - \frac{72}{10} - \frac{2}{9} = \frac{2295}{180} - \frac{1296}{180} - \frac{40}{180} = \frac{959}{180}$