Question

Efectuati:
a)4supra63+1supra18-(2supra5)²×5supra7=
b)(1+3supra2×5supra2):6-1=
c)(12supra35-7supra20)×(-1-1supra6)=
d)(6supra32+5supra24)×30supra38-1supra8=
e)3-2:(5supra8×12supra15)+(1supra3)²=
f)5supra6:1supra3:(12supra8-5supra6)=
g)3supra4-1supra12:1supra4-(4supra3-1supra2)=
h)4supra3:2supra9-(2-3supra4)=
i)8supra3-(14supra20-1supra15):3supra10-8supra15=
j)6supra24+1supra6-(15supra6-3):3supra2=

Answer 1

a) 4/63+1/18-(2/5)²x5/7=
4/63+1/18-4/35=ducem la acelasi numitor
63=7x3²
18=3²x2
35=7x5
calculam cel mai mic multiplu comun
[63,18,35]=7x2x3²x5=630 este numitorul comun
630;63=10 deci cu 10 amplificam I fractie
630:18=35
630:35=18
(4x10+1x35-4x18)/360=
(40+35-72)/360=3/360=1/120

b)(1+3/2x5/2):6-1=
(1+15/2):6-1=
(2/2+15/2)x1/6-1=
(17/2)x1/6-1=
17/12-1=
17/12-12/12=5/12

c)(12/35-7/20)x(1-1/6)=
[(12x4-7x7)/140]x(6/6-1/6)=
[(48-49)/140]x5/6=
-1/140x5/6=-1/168

d)(6/32+5/24)x30/38-1/8=
(6x3+5x4)/96]x30/38-1/8=
[(18+20)/96]x30/38-1/8=
38/96x30/38-1/8=
15/48-1/8=
15/48-6/48=9/48=3/16

e)3-2:(5/8x12/15)+(1/3)²=
3-2:1/2+1/9=
3-2x1/2+1/9=
3-1+1/9=
2+1/9=
18/9+1/9=19/9

f)5/6:1/3:(12/8-5/6)=
5/6x3/1:(3/2-5/6)=
5/2:(9/6-5/6)=
5/2:4/6=5/2x6/4=15/8

g)3/4-1/12:1/4-(4/3-1/2)=
3/4-1/12x4/1-(8/6-3/6)=
3/4-1/3-5/6=
9/12-4/12-10/12=-5/12

h)4/3:2/9-(2-3/4)=
4/3x9/2-(8/4-3/4)=
6-5/4=
24/4-5/4=19/4

i)8/3-((14/20-1/15):3/10-8/15=
8/3-(7/10-1/15)x10/3-8/15=
8/3-(21/30-2/30)x10/3-8/15=
8/3-19/30x10/3-8/15=
8/3-19/9-8/15=
120/45-95/45-24/45=1/45

j)6/24+1/6-(15/6-3):3/2=
6/24+4/24-(15/6-18/6)x2/3=
10/24+3/6x2/3=
5/12+3=5/12+36/12=41/12