Question

efectuati cu factor comun aplicand proprietatile inmultiri fractilor zecimale
a) 10^2x(2,01+3,24+6,75)
b) (7,5+2,5)x(2x3,5+3)x(4x2,6-10,2)

Answer 1

a) 100(2,01+3,24+6,75)=201+324+675=   1200,
sau 100(12,00)=1200.
b) (7,5+2,5)(2*3,5+3)(4*2,6-10,2)=10(7+3)(10,4-10,2)=100*0,2=20.