Question

efectuati folosind formulele:
(x+1)la2
(x+2)la2
(x+3)la2
(x-1)la2
(x-2)la2

Answer 1

[tex] (x+1)^{2}= x^{2} +2*x*1+1^2= x^{2} +2x+1\\ (x+2)^{2}= x^{2} +2*x*2+2^2= x^{2} +4x+4\\ (x+3)^{2}= x^{2} +2*x*3+3^2= x^{2}+ 6x+9\\ (x-1)^{2}= x^{2} -2*x*1+1^2= x^{2} -2x+1\\ (x-2)^{2}= x^{2} -2*x*2+2^2= x^{2} -4x+4\\[/tex]

Answer 2

x la a doua +2x+1
x la a doua+4x+4
x la a doua+ 6x+9
x la a doua-2x+1
x la a doua-4x+4