Question

Efectuati:
/ =linie de fractie
a.(-3/8+1/5)*(-5/14)-(-4/15+7/3)*(- 15/32)
b.13/16+(5/8 * 1/6 -0,4 * 5/4)* ( 2,3 - 25/63 : 5/9 *7/5 -3/10)

Answer 1

a)=(-15/40+8/40)*(-5/14)-(-4/15+35/15)*(-15/32)=(-7/40)*(-5/14)-(31/15)*(-15/32)=(53/560)-(-565/580)=(30740/324800)-(-316400/324800)=(347140/324800)=1,06

Answer 2

[tex]a.(-\frac{3}{8}+\frac{1}{5})*(-\frac{5}{14})-(-\frac{4}{15}+\frac{7}{3})*(-\frac{15}{32})=\\ (\frac{-15+8}{40})*(-\frac{5}{14})-(\frac{-4+35}{15})*(-\frac{15}{32})=\\ (-\frac{7}{40})*(-\frac{5}{14})-\frac{31}{15}*(-\frac{15}{32})=\\ [/tex]
$\frac{1}{16}+\frac{31}{32}=\frac{33}{32}$
[tex]b.\frac{13}{16}+(\frac{5}{8}*\frac{1}{6}-\frac{4}{10}*\frac{5}{4})*(\frac{23}{10}-\frac{25}{63}*\frac{9}{5}*\frac{7}{5}-\frac{3}{10})=\\ \frac{13}{16}+(\frac{5}{48}-\frac{1}{2})*(\frac{23}{10}-\frac{5}{7}*\frac{7}{5}-\frac{3}{10})=\\ \frac{13}{16}-\frac{19}{24}*(\frac{20}{10}-1})=\\ [/tex]
[tex]\frac{13}{16}-\frac{19}{24}*(2-1)=\\ \frac{13}{16}-\frac{19}{24}=\frac{39-38}{48}=\frac{1}{48}[/tex]