Question

efectuati
(x+3)²=
(x+√3)²=
(√7+√2)²
(2x-5y)²=
(-a+5)²=
($\frac{1}{4}$ -x)²=

Answer 1

[tex]a) (x+3)^2= x^{2} +2*x*3+3^2= x^{2} +6x+9\\ b) (x+ \sqrt{3})^2= x^{2} +2\sqrt{3}x+3\\ c) ( \sqrt{7}+ \sqrt{2})^2=(\sqrt{7})^2+2*\sqrt{7}*\sqrt{2}+(\sqrt{2})^2=7+2 \sqrt{14}+2=\\=9+2 \sqrt{14}\\ d) (2x-5y)^2=(2x)^2-2*2x*5y+(5y)^2=4 x^{2} -20xy=25y^{2}\\ e) (-a+5)^2=(5-a)^2=5^2-2*a*5+a^2=25-10a+a^2\\ f) ( \frac{1}{4}-x)^2= (\frac{1}{4})^2-2*\frac{1}{4}*x+ x^{2} = \frac{1}{16}- \frac{1}{2}x+ x^{2}[/tex]

Answer 2

(x+3)²=x²+2*x*3+3²=x²+6x+9
(x+√3)²=x²+2*x*√3+(√3)²=x²+2√3x+3
(√7+√2)²=(√7)²+2*√2*√2*(√2)²=7+2√14+2=9+2√14
(2x-5y)²=(2x)²-2*2x*5y+(5y)²=2x²-10xy+25y²
(-a+5)²=(-a)²+2*(-a)*5+5²=a²-10a+25
( -x)²=( )²-2**x+x²=$\frac{1}{16}$-$\frac{2}{4}$x+x²=$\frac{1}{16}$-$\frac{1}{2}$x+x²
Am simplificat 2 cu 4