Question

Eliminatini radicali dubli:
√7-2√6

Answer 1

$\sqrt{7-2\sqrt{6}} = \sqrt{6-2\cdot 1\cdot \sqrt{6}+1} = \sqrt{(\sqrt{6}-1)^2} = \\ \\ = |\sqrt{6}-1| = \boxed{\sqrt{6}-1}$