Question

este: - calculului 3 la puterea a 2 a [max (0,(21); 0,2(1)) – min (-0,(34); -0,3(4))] 121 131 52​

Answer 1

max[0,(21);  0,2(1)]=0,(21)

min[-0,(34);  -0,3(4)]=-0,3(4)

$\it 3^2\cdot[0,(21)-(-0,3(4)]=9\cdot\Big(\dfrac{21}{99}+\dfrac{34-3}{90}\Big)=\dfrac{21}{11}+\dfrac{31}{10}=$