Question

Este foarte urgent ajutatima doar la 8 ce se vede

Answer 1

[tex]b)~~2\sqrt{3}\times(-\sqrt{2})=-2\sqrt{3}\times\sqrt{2}=-2\sqrt{6}\\\\ c)~~-\frac{2\sqrt{2}}{3}\times\frac{\sqrt{2}}{4}=-\frac{2\sqrt{2}\times\sqrt{2}}{3\times4}=\frac{2\times2}{12}=\frac{4}{12}=\frac{1}{3}\\\\ d)~~(-2\sqrt{3})\Big(-\frac{\sqrt{3}}{2}\Big)=\frac{2\sqrt{3}\times\sqrt{3}}{2}=( \sqrt{3})^2=9\\\\ e)~~-4\sqrt{3}\times\sqrt{7}=-4\sqrt{21}\\\\ f)~~ 6\sqrt{5}\times\Big(-\frac{\sqrt{5}}{30}\Big)=-\frac{6\sqrt{5}\times\sqrt{5}}{30}==-\frac{6\times5}{30}=-\frac{30}{30}=-1[/tex]