Question

Ex. 1
Ajutati-ma va rog!!!

Answer 1

x = franghie = 74 m
y= jumatate din franghie
u= cealalta jumatate
y=16+u
=> u+y=74 inlocuim => u+u+16=74 => 2u=74-16 <=> 2u=58 => u=29
y= 16+29 => y=45
b) a+b+c=155kg
a=28+b
c=22+b
inlocuim => 28+b + b + 22 + b = 155 <=> 3b + 50 = 155 => 3b = 105 => b=35
a = 28+b => a= 35+28 = 63
c= 22+ 35 => c = 57

Answer 2

I= |__________|__+16_|
II=|__________|              ⇒ 2*|__________|+16=74(m)
                                        ⇒ 2*|__________| = 74-16 = 58(m)
                                        ⇒    |__________| =58:2=29 (m)
⇒ I = 29+16=45(m)  si  II = 29(m)
......................................................................................................
I  = |_____|_28_|
II = |_____|
III= |_____|_22_|     ⇒ 3*|____|+50=155(kg)
                                ⇒ 3*|____| = 105(kg)
                                ⇒    |____| = 105:3=35(kg)
⇒ I  = 35+28=63 kg ; II  = 35 kg  ; III = 35+22 = 57 kg .