Question

Ex 2,3 de la partea a doua va rog ,dau funda

Answer 1

Răspuns:

Explicație pas cu pas:

2. a+b=19

   a/b=3 r 3 ⇒a=3·b+3

⇒3·b+3+b=19

4b+3=19

4b=16

b=4 ⇒a=19-b=19-4=15

3. a+b+c=502

b=3a

c/b=7 r 2 ⇒c=7b+2=7·3a+2=21a+2

a+b+c=502

a+3a+21a+2=502

25a=500 ⇒a=20 ⇒b=3a=3·20=60  ⇒c=7b+2=7·60+2=420+2=422

Answer 2

Explicație pas cu pas:

2) a+b=19

a:b=3 rest 3

a=3•b+3 apoi inlocuim in prima relatie

a+b=19; 3•b+3+b=19

4•b+3=19 ; 4•b=19-3

4•b=16 ; b=16:4 ; b=4

a+4=19 ; a=19-4 ; a=15

3) a+b+c=502

b=3•a

c:b=7 rest 2; c=7•b+2; c=7•3•a+2

inlocuim:

a+3•a+21•a+2=502

25•a+2=502; 25•a=502-2

25•a=500 ; a=500:25

a=20

b=3•20 ; b=60

c=7•60+2 ; c=420+2 ; c=422