Question

ex 20 va rog rapid!!!!

Answer 1

Răspuns:

$x$ ∈ $[\frac{-11}{2} , \frac{3}{4} ]$

Explicație pas cu pas:

$\frac{2x+3}{2} \leq \frac{3(x+3)}{5} \leq \frac{4x+13}{6} \\15(2x+3)\leq 18(x+3)\leq 5(4x+13)\\30x+45\leq 18x+54\leq 20x+65\\\\30x+45\leq 18x+54\\12x\leq 9\\x\leq \frac{3}{4} \\\\\18x+54\leq 20x+65\\-11\leq 2x\\x\geq \frac{-11}{2}$

$x$ ∈ $[\frac{-11}{2} , \frac{3}{4} ]$